2b^2-15b-50=0

Solution for 2b^2-15b-50=0 equation:

2b^2-15b-50=0

a = 2; b = -15; c = -50;
Δ = b2-4ac
Δ = -152-4·2·(-50)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-25}{2*2}=\frac{-10}{4}
=-2+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+25}{2*2}=\frac{40}{4}
=10
$